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Calculate the emf of the cell at 298 k mg

WebAug 7, 2024 · A solution containing 30 g of non-volatile solute exactly in 90 g of water has a vapour pressure of 2.8 kPa at 298 K. Further 18 g of water is added to this solution. The new vapour pressure becomes 2.9 kPa at 298 K. Calculate (i) the molecular mass of solute and (ii) vapour pressure of water at 298 K. (Comptt. Delhi 2012) Answer: WebDec 21, 2013 · Warning! VERY long answer! You can calculate the cell potential for an electrochemical cell from the half-reactions and the operating conditions. > The first step …

3.1 How would you determine the standard electrode potential …

WebScience Chemistry Calculate emf and AG° for the following cell at 298 K:Mg(s) Mg2+(10-3M) CU2+(10-3M) CU(S)Given:E0mg2+/mg = – 2.36 V andE0cu2+/cu = +0.34 V, [1 F … WebDec 22, 2013 · Warning! VERY long answer! You can calculate the cell potential for an electrochemical cell from the half-reactions and the operating conditions. > The first step is to determine the cell potential at its standard state — concentrations of 1 mol/L and pressures of 1 atm at 25°C. The procedure is: Write the oxidation and reduction half … harlingen flights to houston https://sexycrushes.com

Important Questions for Class 12 Chemistry Chapter 3 ... - Learn …

WebApr 4, 2024 · Hence the emf of the following cell at 298 K is equal to $ \text{0}\text{.53 V} $ . Note: The Nernst equation relates the reduction potential of an electrochemical reaction (half –cell or full cell) to the standard reduction potential, temperature and the activities (often approximated by the concentrations) of the chemical species that are ... WebFor the given cell representation, the cell reaction will be Mg(s) + Cu 2 + (0.0001 M) → Mg 2 + (0.001 M) + Cu(s) The standard emf of the cell will be given by WebStart your trial now! First week only $4.99! arrow_forward Literature guides Concept explainers Writing guide Popular textbooks Popular high school textbooks Popular Q&A Business Accounting Business Law Economics Finance Leadership Management Marketing Operations Management Engineering AI and Machine Learning Bioengineering Chemical … channing the clock in vivado hls

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Calculate the emf of the cell at 298 k mg

Write the Nernst equation and emf of the following cells at 298 K

WebThe cell in which the following reaction occurs: 2Fe 3+ (aq) + 2I – (aq) → 2Fe 2+ (aq) + I 2 (s) has E 0 cell = 0.236 V at 298 K. Calculate the standerd Gibbs energy and the equilibrium constance of the cell reaction. WebΔrG0 can be calculated by measuring the emf of the cell (E0cell ) Knowing ΔrG0 , the equilibrium constant K can be calculated. ΔrG0 = - RT lnK. ΔrG0 = - 2.303 RT log Kc Example 3.3: The standard electrode potential for Daniell cell is 1.1V. Calculate the standard Gibbs energy for the reaction: Zn(s) + Cu2+(aq) ⎯→ Zn2+(aq) + Cu(s)

Calculate the emf of the cell at 298 k mg

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WebDec 10, 2024 · The electromotive force (EMF) is the maximum potential difference between two electrodes of a galvanic or voltaic cell. This quantity is related to the tendency for an element, a compound or an ion to acquire (i.e. gain) or release (lose) electrons. For example, the maximum potential between Zn and Cu of a well known cell.

WebJun 4, 2014 · Calculate the emf of the following cell at 298 K: Fe(s) Fe 2+ (0.001M) ... A Cu rod is dipped in 0.1M CuSo4 solution.Calculate the potential of this half cell if CuSo4 undergoes 90% dissociation at 25 C. Asked by ankitathapliyal097 24 Jul, 2024, 10:05: PM. ANSWERED BY EXPERT. WebFeb 20, 2024 · Calculate the emf of the following cell at 298 K. 2Cr(s)+3Fe2+(0.1M) 2Cr3+(0.01M)+3Fe(s) Given, E(Cr3+/Cr )∘ =−0.74 V,E(Fe2+/Fe)∘ =−0.44 V Delhi 2016 …

WebWe can use the information given and the Nernst equation to calculate E cell. Moreover, because the temperature is 25°C (298 K), we can use Equation 11.4.5 instead of Equation 11.4.2. The overall reaction involves the net transfer of two electrons: 2Ce4 + ( aq) + 2e − → 2Ce3 + ( aq) 2Cl − ( aq) → Cl2 ( g) + 2e −. WebStudy with Quizlet and memorize flashcards containing terms like Consider a redox reaction for which E is a negative number. a. What is the sign of delta G for the reaction? b. Will the equilibrium constant K for the reaction be larger or smaller than 1? c. Can an electrochemical cell based on this reaction accomplish work on its surroundings?, What …

WebAnswer to Solved 7. (11.7) Calculate the emf of the following. This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn …

WebApr 4, 2024 · Hence the emf of the following cell at 298 K is equal to $ \text{0}\text{.53 V} $ . Note: The Nernst equation relates the reduction potential of an electrochemical reaction … channing texas real estateWebFor the cell M g (s) ∣ M g 2 + (a q) ∣ ∣ A g + (a q) ∣ A g (s), calculate the equilibrium constant at 2 5 o C and the maximum work that can be obtained during operation of cell. Given E … channing texas to amarillo texasWeb(b) Calculate the emf of the cell Zn/Zn2+ (0.1 M) Cd2+ (0.01 M)/Cd at 298 K, [Given and Or (a) Account for the following: (i) Alkaline medium inhibits the rusting of iron. (ii) Iron does not rust even if the zinc coating is broken in a galvanised iron pipe. harlingen flights to vegas